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PEAFOWL GENETICS---ITS NO SECRET ANYMORE
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THE INDIA BLUE GENE (including black shoulder and white)
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BASIC STUFF:
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A few terms and abbreviations needed to understand these pages.
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'D'--Dominant---a dominant gene---only one copy of a 'D' gene is needed for that trait to be seen.
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Dominant genes will ALWAYS be in capital letters.
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'r'--recessive---a recessive gene---two copies of a 'r' gene are needed for that trait to be seen.
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recessive genes will ALWAYS be in lower case.
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'Id'--Incomplete dominant---a blending of the two.---"id" genes will express themselves in various ways.
I will indicate if and when an 'Id' gene is being discussed.
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GENOTYPE---this is the genetic make-up of the bird.
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PHENOTYPE---this is what the bird looks like---physically.
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Heterozygous---the bird has 2 different genes. (Bb, BT, Bc, etc.)
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Homozygous----the bird has 2 identical copies. (BB, bb, TT, etc.)
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This is a breeding of an India blue to an India blue.
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Each bird receives 1 gene from each parent.
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In peafowl, Blue (B) is dominant.
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This is a breeding of b.s. to b.s. (bb x bb) all 'r' genes.
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This works the same as with the india blues
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because each parent is homozygous bb.
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BB X BB= 100% BB
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blue x blue
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GENOTYPE = 100% homozygous Dominant BB
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PHENOTYPE= 100% India blue
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bb x bb= 100% bb
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b.s. x b.s.
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GENOTYPE=100% homozygous recessive bb
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PHENOTYPE=100% black shoulder
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Now, let's cross a Bb to a Bb.
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This is heterozygous blue/b.s. to heterozygous blue/b.s.
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Each parent bird has one Dominant gene
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and one recessive gene
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This is a breeding of an India blue to a black
shoulder.
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The black shoulder is a recessive trait.
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You need 2 b genes to get black shoulder.
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Bb X Bb=
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GENOTYPE=25% BB 50%Bb 25%bb
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PHENOTYPE= 75% blue 25% b.s.
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BB= homozygous dominant india blue
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Bb= heterozygous india blue
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bb= homozygous recessive black shoulder
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From this cross we got 3 types of birds...(BB, Bb,bb)
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and two colors...blue and b.s.
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BB X bb=100% Bb
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blue x b.s.
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GENOTYPE= 100% heterozygeous blue/b.s. (Bb)
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PHENOTYPE=100% India blue.
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These birds 'look' india blue, because the 'B'
gene is dominant but, they carry one hidden
gene for b.s.
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Now let's try Bb x bb
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This will be a breeding of the heterozygous blue (Bb)
with a homozygous (pure) black shoulder (bb)
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Three recessive 'b' genes involved.
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Bb X bb=
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GENOTYPE=50%Bb 50%bb
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PHENOTYPE=50% blue 50% b.s.
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Bb= heterozygous india blue
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bb= homozygous recessive black shoulder
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Notice we didn't get any homozygous BB
blues in this example.
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At one time or another, the pure white peafowl is always everyones favorite.
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The white peafowl is NOT albino.
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It is an incomplete dominant mutation of the India Blue.
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We will refer to the white gene as 'T'. ('W' has already been taken)
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Homozygous india blue (BB) to a homozygous white (TT)
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White is Id (incomplete dominant),
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so some new things will happen
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This will be a white to white mating.
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Both parents are TT, homozygous (pure) white.
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BB X TT=
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GENOTYPE= 100% BT
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PHENOTYPE= 100% hetero india blue, with white flight feathers
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Because the white is Id, it will let you know it's there by showing up
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in a minimal way.
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The india blue colored bird will have white flight feathers or
sometimes a white throat patch.
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TT X TT= 100% TT
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GENOTYPE= 100% homozygous TT
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PHENOTYPE= 100% white
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Now we will use those BT birds.
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Mate a BT to a BT.
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Each parent is heterozygous.
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One dominant 'B' gene, and one Id 'T' gene.
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Mate a BT to a TT.
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You now have 3 'T' genes to work with.
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Do you think you'll get more whites?
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Let's see.
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BT X BT=
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GENOTYPE=25%BB 50%BT 25%TT
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PHENOTYPE=25% blue 50% blue w/w 25% white
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BB- homozygous India blue
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BT- heterozygous India blue w/ white f.f.
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TT- homozygous white
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BT X TT=
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GENOTYPE=50% BT 50% TT
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PHENOTYPE=50% blue w/w 50% white
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BT- hetero India blue w/ white flight feathers
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TT- homozygous white
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I almost forgot one.
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BB X BT---That's pure india blue X hetero blue/white
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BB X BT=
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GENOTYPE= 50% BB 50%BT
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PHENOTYPE=50% blue 50% blue w/w
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BB- homozygous India blue
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BT- hetero blue/white
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LET'S WORK WITH BLACK SHOULDERS AND WHITES
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First we'll do a bb X TT
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That's a black shoulder X white
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Homozygous TT white X hetero Tb white
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TT X Tb=
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GENOTYPE= 50% Tb 50% TT
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PHENOTYPE= 50% blue 50% white
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TT X bb=
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GENOTYPE= 100% hetero Tb
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PHENOTYPE= 100% blue
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Heterozygous Tb X hetero Tb
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Tb X Tb=
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GENOTYPE= 25% TT 50% Tb 25% bb
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PHENOTYPE= 25% white 50% blue 25% b.s.
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Heterozygous Tb white X homozygous bb
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Tb X bb=
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GENOTYPE= 50% Tb 50% bb
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PHENOTYPE=50% blue 50% b.s.
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UNITED WE STAND
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BIN LADEN WILL FALL
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